Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 6 - Analyzing Accumulated Change: Integrals in Action - 6.1 Activities - Page 422: 5

Answer

$\infty$

Work Step by Step

$\int ^{\infty }_{a}f\left( x\right) dx=\lim _{N\rightarrow \infty }F\left( N\right) -F\left( a\right) \Rightarrow $ $\int ^{\infty }_{0.36}9.6x^{-0.432}dx=\lim _{x\rightarrow \infty }\left( \dfrac {9.6}{-0.432+1}\times x^\left( -0.432+1\right) \right) -( \dfrac {9.6}{-0.432+1}\times 0.36^\left( -0.432+1\right) ) = \lim _{x\rightarrow \infty }16.9\times x^{0.568}-9.46 =\infty $
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