Answer
$-2\times10^{-2}=-0.02$
Work Step by Step
$$\int ^{a}_{-\infty }f\left( x\right) dx=F\left( a\right) -\lim _{N\rightarrow -\infty }F\left( N\right) \Rightarrow $$
$\int ^{10}_{-\infty }4x^{-3}dx=\dfrac {4}{-3+1}\times 10^{-3+1}-\lim _{N\rightarrow -\infty }\dfrac {4}{-3+1}\times N^{-3+1}=-2\times 10^{-2}-\lim _{N\rightarrow -\infty }-2N^{-2}=-2\times10^{-2}$
