Answer
$\dfrac {x^{2}}{4}+\dfrac {1}{2}\ln x+c$
Work Step by Step
$$\int \dfrac {x^{2}+1}{2x}dx=\int \left( \dfrac {x^{2}}{2x}dx+\dfrac {1}{2x}dx\right) =\int \left( \dfrac {x}{2}+\dfrac {1}{2x}\right) dx=\dfrac {x^{2}}{4}+\dfrac {1}{2}\ln x+c$$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 5 - Accumulating Change: Limits of Sums and the Definite Integral - 5.9 Activities - Page 409: 18
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