Answer
$-8x^{-2}+\dfrac {8}{3}x^{\frac {3}{2}}+x+c $
Work Step by Step
$\int \left( \dfrac {16}{x^{3}}+4\sqrt {x}+1\right) dx=\int \left( 16\times x^{-3}+4\times x^{\frac {1}{2}}+1\right) =\dfrac {-16}{2}x^{-2}+4\times \dfrac {2}{3}x^{\frac {3}{2}}+x+c==-8x^{-2}+\dfrac {8}{3}x^{\frac {3}{2}}+x+c $
