Answer
$$j'\left( x \right) = 6\left( {\ln 1.7} \right)\left( {{{1.7}^{3x + 4}}} \right)$$
Work Step by Step
$$\eqalign{
& j\left( x \right) = 2\left( {{{1.7}^{3x + 4}}} \right) \cr
& {\text{Calculate the derivative of the function}} \cr
& j'\left( x \right) = \frac{d}{{dx}}\left( {2\left( {{{1.7}^{3x + 4}}} \right)} \right) \cr
& {\text{Compute the derivative}} \cr
& j'\left( x \right) = 2\left( {\ln 1.7} \right)\left( {{{1.7}^{3x + 4}}} \right)\frac{d}{{dx}}\left( {3x + 4} \right) \cr
& j'\left( x \right) = 2\left( {\ln 1.7} \right)\left( {{{1.7}^{3x + 4}}} \right)\left( 3 \right) \cr
& {\text{simplifying}} \cr
& j'\left( x \right) = 6\left( {\ln 1.7} \right)\left( {{{1.7}^{3x + 4}}} \right) \cr} $$
