Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 3 - Determining Change: Derivatives - 3.6 Activities - Page 237: 2

Answer

$$f'\left( x \right) = 6{e^x} + x{e^x}$$

Work Step by Step

$$\eqalign{ & f\left( x \right) = \left( {x + 5} \right){e^x} \cr & {\text{Calculate the derivative of the function}} \cr & f'\left( x \right) = \frac{d}{{dx}}\left( {\left( {x + 5} \right){e^x}} \right) \cr & {\text{use the product rule }} \cr & f'\left( x \right) = {e^x}\frac{d}{{dx}}\left( {x + 5} \right) + \left( {x + 5} \right)\frac{d}{{dx}}\left( {{e^x}} \right) \cr & {\text{compute derivatives}} \cr & f'\left( x \right) = {e^x}\left( 1 \right) + \left( {x + 5} \right){e^x} \cr & {\text{multiply}} \cr & f'\left( x \right) = {e^x} + x{e^x} + 5{e^x} \cr & f'\left( x \right) = 6{e^x} + x{e^x} \cr} $$
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