Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 3 - Determining Change: Derivatives - 3.5 Activities - Page 233: 15

Answer

(a)$f(x)=4(e^{1.5x})(1.5^x)$ (b)$f^{'}(x)=(4 \ln 1.5)(e^{1.5x})(1.5^x)+6(1.5^x)e^{1.5x} $

Work Step by Step

$g(x)=2e^{1.5x}$ $h(x)=2 (1.5^x)$ (a) Let $f(x)=g(x)h(x)$ $f(x)=2e^{1.5x}\times2(1.5^x)=4(e^{1.5x})(1.5^x)$ (b)Taking derivative of f(x) with respect to x $f^{'}(x)=4(e^{1.5x})\frac{d(1.5^x)}{dx}+4(1.5^x)\frac{d(e^{1.5x})}{dx}$ $f^{'}(x)=4(e^{1.5x})(1.5^x)(\ln 1.5)+4(1.5^x)e^{1.5x} \frac{d(1.5x)}{dx}$ $f^{'}(x)=4(e^{1.5x})(1.5^x)(\ln 1.5)+4(1.5^x)e^{1.5x} (1.5)\frac{d(x)}{dx}$ $f^{'}(x)=4(e^{1.5x})(1.5^x)(\ln 1.5)+4(1.5^x)e^{1.5x} (1.5)$ $f^{'}(x)=(4 \ln 1.5)(e^{1.5x})(1.5^x)+4(1.5)(1.5^x)e^{1.5x} $ $f^{'}(x)=(4 \ln 1.5)(e^{1.5x})(1.5^x)+6(1.5^x)e^{1.5x} $
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