Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 3 - Determining Change: Derivatives - 3.5 Activities - Page 233: 14

Answer

(a)$f(x)=5e^{2x}(20x^3-30)$ (b)$f^{'}(x)=[10e^{2x}](20x^3-30)+5e^{2x} [60x^2] $

Work Step by Step

$g(x)=5e^{2x};h(x)=20x^3-30$ (a) Let $f(x)=g(x) h(x)$ $f(x)=5e^{2x}(20x^3-30)$ (b) Taking derivative of f(x) with respect to x, using product rule $f^{'}(x)=g^{'}(x)h(x)+g(x)h^{'}(x)$ $f^{'}(x)=[5(2)e^{2x}](20x^3-30)+5e^{2x} [20(3)x^2-0] $ $f^{'}(x)=[10e^{2x}](20x^3-30)+5e^{2x} [60x^2] $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.