Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 3 - Determining Change: Derivatives - 3.4 Activities - Page 224: 27

Answer

$\frac{(\ln 2)2^{\ln x}}{x}$

Work Step by Step

Let $y=2^{\ln x}$ Substitute $t= \ln x$ Then, $y= 2^{t}$ $\ln y= t \ln 2$ Differentiating both sides with respect to t, we get $\frac{1}{y}\frac{dy}{dt}=\ln 2$ or $\frac{dy}{dt}=y \ln 2= 2^{t}\ln2= 2^{\ln x}\ln2$ $\frac{dt}{dx}=\frac{1}{x}$ According to the chain rule, $\frac{dy}{dx}= \frac{dy}{dt}\cdot\frac{dt}{dx}=(\ln2 )2^{\ln x}\cdot\frac{1}{x}=\frac{(\ln 2)2^{\ln x}}{x}$
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