Answer
inside: $g(x)=x^5-1$
outside: $f(g) =3g^{-3}$
derivative: $f'(x)=-9(x^5-1)^{-4}*5x^4$
Work Step by Step
Rewrite the function as $3(x^5-1)^{-3}$
Use the chain rule to take the derivative $\frac{d}{dx}f(g(x))=f'(g(x))g'(x)$
To find the inside, you take the number inside the parenthesis.
To find the outside, you exchange the parenthesis to a variable.
Then take its derivative and put it together.