Answer
$j'(x)=7(1.3^x)* ln1.3-e^x$
Work Step by Step
We solve this problem by simplifying the problem to $10(1.05095)^x$ then we implement the number raised to a variable rule: $\frac{d}{dx}(a^x)=ln (a) * a^x$. and since $f(x) = e^x $ and $f '(x) = e^x$ are equal, $e^x$ stays the same.
