Answer
$\ln(2)y^{\ln(2) - 1}$
Work Step by Step
For $m(y)=y^{n}$,
$\frac{dm}{dy} = ny^{n-1}$
Therefore, for $m(y)=y^{\ln(2)}$
$\frac{dm}{dy} =\ln(2)y^{\ln(2) - 1}$
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