Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 3 - Determining Change: Derivatives - 3.1 Activities - Page 198: 8

Answer

$\ln(2)y^{\ln(2) - 1}$

Work Step by Step

For $m(y)=y^{n}$, $\frac{dm}{dy} = ny^{n-1}$ Therefore, for $m(y)=y^{\ln(2)}$ $\frac{dm}{dy} =\ln(2)y^{\ln(2) - 1}$
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