Answer
$6$
Work Step by Step
$\lim\limits_{h \to 0}\frac{(h+3)^2-3^2}{h}=\lim\limits_{h \to 0}\frac{6h+h^2}{h}=\lim\limits_{h \to 0}(6+h)=6$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 1 - Ingredients of Change: Functions and Limits - 1.3 Activities - Page 31: 32
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