Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 1 - Ingredients of Change: Functions and Limits - 1.1 Activities - Page 11: 41

Answer

$a)$ For $75$ feet the maximum time is $39.18$ minutes and for $95$ feet is $23.04$ minutes. $b)$ The maximum depth possible in a dive of $20$ minutes is $100.32$ feet.

Work Step by Step

$a)$ In this exercise we just need to evaluate the value of the function when $x=75$ and $x=95$: $t(75)=286.93(0.9738)^{75}\approx39.18 $ minutes $t(95)=286.93(0.9738)^{95}\approx23.04 $ minutes $b)$ Here we just need to solve the following equation $t(x)=20$, so then we have: $t(x)=20 ⇔ 286.93(0.9738)^{x}=20⇔(0.9738)^{x}=\frac{20}{286.93}⇔$ $⇔e^{x\ln0.9738}=\frac{20}{286.93}⇔x\ln0.9738=\ln(\frac{20}{286.93})⇔$ $⇔x=\ln(\frac{20}{286.93}):\ln0.9738⇔x\approx100.32 $ feet
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