Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 7 - Techniques of Integration - 7.8 Improper Integrals - 7.8 Exercises - Page 574: 6

Answer

Divergent

Work Step by Step

Let \[I=\int_{0}^{\infty}\frac{1}{\sqrt[4]{1+x}}dx\;\;\;\ldots(1)\] \[I=\lim_{t\rightarrow \infty}\int_{0}^{t}\frac{1}{\sqrt[4]{1+x}}dx\;\;\;\ldots(2)\] \[I=\lim_{t\rightarrow \infty}\left[\frac{4}{3}(1+x^2)^{\frac{3}{4}}\right]_{0}^{t}\] \[I=\lim_{t\rightarrow \infty}\left[\frac{4}{3}(1+t^2)^{\frac{3}{4}}-\frac{4}{3}\right]\] \[I=\infty\] Since limit on R.H.S. of (2) does not exist So given improper integral (1) is divergent.
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