Answer
False
Work Step by Step
Let suppose $x=e$, then $(ln~x)^6=(ln~e)^6=(1)^6=1$, but
$6ln~x=6ln~e$
$6ln~e=6.1\ne1$.
However, $ln(x)^6=6ln~x$ for $x>0$.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - Review - True-False Quiz - Page 504: 9
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