Answer
$$F'(z) =\frac{2z }{\ln 10(1+z^2)}$$
Work Step by Step
Given $$F(z)=\log_{10}\left(1+z^2\right)$$
Then
\begin{align*}
F(z)&= \frac{\ln\left(1+z^2\right)}{\ln 10}\\
F'(z)&=\frac{2z }{\ln 10(1+z^2)}\\
\end{align*}
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