Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 36

Answer

$$F'(z) =\frac{2z }{\ln 10(1+z^2)}$$

Work Step by Step

Given $$F(z)=\log_{10}\left(1+z^2\right)$$ Then \begin{align*} F(z)&= \frac{\ln\left(1+z^2\right)}{\ln 10}\\ F'(z)&=\frac{2z }{\ln 10(1+z^2)}\\ \end{align*}
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