Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 17

Answer

$$x= \sqrt{e+1}$$

Work Step by Step

Given $$\ln (x+1)+\ln (x-1)=1$$ Then \begin{align*} \ln (x+1)+\ln (x-1)&=1\\ \ln (x+1)(x-1)&=1\\ \ln (x^2-1)&=\ln e\\ x^2-1&=e \end{align*} Hence $$x= \sqrt{e+1}$$
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