Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 12

Answer

(a) $\pi $ (b) $\dfrac{\sqrt{3}}{3} $

Work Step by Step

Given (a) $\ln e^{\pi}$ Since $\ln x^a=a\ln x$, then $\ln e^{\pi}=\pi \ln e=\pi$ (b)$\tan(\arcsin 1 /2)$ Since $\arcsin (1 /2)=\frac{\pi }{6}$, then $\tan(\pi/6) =\frac{\sqrt{3}}{3}$
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