Answer
$-1.5$
Work Step by Step
From the given graph, we have
$\lim\limits_{x \to 2} \dfrac{f(x)}{g(x)} = \lim\limits_{x \to 2} \dfrac{1.5(x-2)}{(2-x)} = \dfrac{0}{0}$
This shows is an indeterminate form.
Thus, applying L'Hospital, we get
$= \lim\limits_{x \to 2} \dfrac{1.5(x-2)}{(-1)(x-2)}$
$=-1.5$
