Answer
$2x\cosh{(x^2)} $
Work Step by Step
Given: $h(x)=\sinh {(x^2)}$
Now, $h'(x)=\frac{d}{dx}(\sinh {(x^2)})$
On applying the chain rule, we have
$h'(x)=(\dfrac{d\sinh {(x^2)}}{dx^2})(\dfrac{dx^2}{dx})$
or, $=(\cosh {(x^2)})(2x)$
or, $=2x\cosh{(x^2)} $