Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.6 Inverse Trigonometric Functions - 6.6 Exercises - Page 482: 44

Answer

$\frac{\pi}{3}$

Work Step by Step

The rational function inside the arcsine is continous for all $x\in \mathbb R$ so the limit is equal to: $$\arccos(\lim_{x \to \infty}\frac{1+x^2}{1+2x^2})$$ $$\arccos(\lim_{x \to \infty}\frac{x^2(1+\frac{1}{x^2})}{x^2(2+\frac{1}{x^2})})$$ $$\arccos(\lim_{x \to \infty}\frac{1+\frac{1}{x^2}}{2+\frac{1}{x^2}})$$ $$\arccos(\frac{1+0}{2+0})=\arccos(\frac{1}{2})=\frac{\pi}{3}$$
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