Answer
$x^{\sqrt 5}=e^{\sqrt 5lnx}$
Work Step by Step
As we know that $e^{lnx}=x$
Take exponent to the given term $x^{\sqrt 5}$.
$x^{\sqrt 5}=e^{lnx^{\sqrt 5}}$
Since, $logx^{y}=xlogy$
Hence, $x^{\sqrt 5}=e^{\sqrt 5lnx}$
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