Answer
$4^{-\pi}=e^{-\pi ln4}$
Work Step by Step
As we know that $e^{lnx}=x$
Take exponent to the given term $4^{-\pi}$.
$4^{-\pi}=e^{ln4^{-\pi}}=x$
Since, $logx^{y}=xlogy$
Hence, $4^{-\pi}=e^{-\pi ln4}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise - Page 463: 3
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
