Answer
$\pi\ln 2$
Work Step by Step
$$V=\pi\int_{0}^{1}\left(\frac{1}{\sqrt{x+1}}\right)^{2}dx$$
$$V=\pi\int_{0}^{1}\frac{1}{x+1}dx$$
$$V=\pi[\ln(x+1)]_{0}^{1}=\pi\ln(1+1)-\pi\ln(0+1)=\pi\ln 2$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises - Page 438: 85
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
