Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises: 82

Answer

$\int x2^{x^{2}}dx=\frac{1}{2}\frac{2^{{x^{2}}}}{ln2}+constant$

Work Step by Step

Evaluate the integral $\int x2^{x^{2}}dx$. Consider $x^{2}=t$ and $\frac{d}{dx}x^{2}=dt$ $2xdx=dt$ $xdx=\frac{dt}{2}$ Now, $\int x2^{x^{2}}dx=\int 2^{t}\frac{dt}{2}$ $=\frac{1}{2}\frac{2^{t}}{ln2}+constant$ Hence, $\int x2^{x^{2}}dx=\frac{1}{2}\frac{2^{{x^{2}}}}{ln2}+constant$
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