Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises: 83

Answer

$\frac{1}{e+1}+e-1$

Work Step by Step

$\int_0^1(e^x+x^e)dx$ $=(e^x+\frac{x^{e+1}}{e+1})|_0^1$ $=(e^1+\frac{1^{e+1}}{e+1})-(e^0+\frac{0^{e+1}}{e+1})$ $=(e+\frac{1}{e+1})-(1+0)$ $=e+\frac{1}{e+1}-1$ $=\frac{1}{e+1}+e-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.