Answer
$(3x^2+x-5)e^x$
Work Step by Step
$\frac{d}{dx}(3x^2-5x)e^x$
$=(3x^2-5x)\frac{d}{dx}e^x+e^x\frac{d}{dx}(3x^2-5x)$
$=(3x^2-5x)e^x+e^x(6x-5)$
$=(3x^2-5x+6x-5)e^x$
$=(3x^2+x-5)e^x$
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