## Calculus 8th Edition

$\infty$
Need to find the limit for $\lim\limits_{x \to2^{-}}e^{\frac{3}{(2-x)}}$. Consider $y=\lim\limits_{x \to2^{-}}e^{\frac{3}{(2-x)}}$ when ${x \to 2^{-}}$ then $(2-x) \to 0^{+}$ Thus, $\lim\limits_{x \to2^{-}}e^{\frac{3}{(2-x)}}=e^{\infty}$ Hence, the limit for $\lim\limits_{x \to2^{-}}e^{\frac{3}{(2-x)}}$ is $\infty$.