## Calculus 8th Edition

Since, change of base formula defines $\log_{a}x=\frac{logx}{loga}$ Therefore, (a) $\log_{5}10=\frac{log10}{log5}$ Hence, $\log_{5}10=\frac{log10}{log5}=1.430677$ (b) $\log_{3}57=\frac{log57}{log3}$ Hence, $\log_{3}57=\frac{log57}{log3}=3.680144$ (c) $\log_{2}\pi=\frac{log\pi}{log2}$ Hence, $\log_{2}\pi=\frac{log\pi}{log2}$ =1.651496