Answer
$lnb+2lnc-3lnd=ln[\frac{bc^{2}}{d^{3}}]$
Work Step by Step
To express the quantity as a single quantity we need to follow some steps.
1.Use logarithmic properties $ln(pq) = lnp+lnq$ and $ln(p)^{m}= m lnp$.
$lnb+2lnc-3lnd=lnb+lnc^{2}-lnd^{3}$
$= ln(bc^{2})-ln(d^{3})$
$=ln[\frac{bc^{2}}{d^{3}}]$
Hence,
$lnb+2lnc-3lnd=ln[\frac{bc^{2}}{d^{3}}]$
