## Calculus 8th Edition

$\int_e^6\frac{dx}{xlnx}=ln(ln6)$
Consider $lnx=u$ and $\frac{1}{x}dx=du$ Thus, $\int_e^6\frac{dx}{xlnx}=\int_1^{ln6} \frac{du}{u}$ $=|lnu|_1^{ln6}$ $=|ln(ln6)-ln1|$ Hence, $\int_e^6\frac{dx}{xlnx}=ln(ln6)$