## Calculus 8th Edition

$4512$ liters
An oil storage tank ruptures at time $t=0$ and oil leaks from the tank at a rate of $r(t)=100 e^{-0.01t}$ liters per minute. Consider $r'(t)$ amount of oil leaks out during first hour. $r'(t)=\int _{0}^{60}r(t)dt$ This implies $r'(t)=\int _{0}^{60} 100 e^{-0.01t}dt$ $=100(\frac{e^{-0.01t}}{-0.01})_{0}^{60}$ $=4512$ liters Hence, the amount of oil leaks out during first hour will be $4512$ liters.