Answer
$(f^{-1})'(5)=\frac{3}{2}$
Work Step by Step
Since $f(4)=5$, this implies $f^{-1}(5)=4$ and so, by theorem 7, $(f^{-1})'(5)=\frac{1}{f'(f^{-1}(5))}=\frac{1}{f'(4)}=\frac{3}{2}.$
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