Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.1 Inverse Functions - 6.1 Exercises: 11

Answer

This function is not one to one.

Work Step by Step

Let $y=g(x)=1-\sin x$. This function is not one-to-one because $y=1$ for every $x$ of the form of $x=k\pi$, where $k$ is integer because $\sin k\pi=0$. This means that to the same value of the function correspond multiple values of the argument so the function is not one-to-one.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.