Answer
$b=1$
Work Step by Step
$$\frac{f(b)-f(0)}{b-0}=3$$
$$\frac{2+6b-3b^{2}-2}{b}=3$$
$$\frac{6b-3b^{2}}{b}=3$$
$$6-3b=3$$
$$3b=6-3$$
$$3b=3$$
$$b=1$$
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