Chapter 4 - Integrals - 4.4 Indefinite Integrals and the Net Change Theorem - 4.4 Exercises - Page 336: 19

$-\frac{10}{3}$

We evaluate the integrand $\int x^2 -3 dx$, which equals $\frac {x^3}{3} -3x\Big|_-2^3$ Substituting 3 and -2 into $x$, we get $(\frac {3^3}{3} - 3(3)) - (\frac {2^3}{3} - 3(2)) $ $ = (0) - (\frac{8}{3} - 6) = -\frac{10}{3}$