Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.3 The Fundamental Theorem of Calculus - 4.3 Exercises - Page 328: 50

Answer

$f(x)=\frac{4}{x^3}$ is not continuous in $(-1,2)$, and hence FTC-2 cannot be applied.

Work Step by Step

According to the fundamental theorem of calculus, $\int_a^bf(x)dx = F(b)-F(a)$, where $F$ is the antiderivative of $f$ or $F'=f$, provided that $f$ is continuous in $(a, b)$. Here, $\frac{4}{x^3}$ is not continuous in $(-1,2)$ and as an infinite discontinuity at $x=0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.