Answer
$1.4$
Work Step by Step
Since $4$ is between $2$ and $8$ then by the Integral of the Function over Adjacent Intervals it follows that:
$\int_{2}^{8}f(x)dx=\int_{2}^{4}f(x)dx+\int_{4}^{8}f(x)dx$
Substitute each definite integral by its value:
$7.3=5.9+\int_{4}^{8}f(x)dx$
$7.3-5.9=\int_{4}^{8}f(x)dx$
$1.4=\int_{4}^{8}f(x)dx$
