Answer
$\int_2^{5}x\sqrt{1+x^{3}}dx$
Work Step by Step
By identification of terms between the definition of the definite integral and the given limit it follows:
$$f(x)=x\sqrt{1+x^{3}},a=2,b=5$$
so the given limit is equal to:
$$\int_2^{5}x\sqrt{1+x^{3}}dx$$