Answer
$\int_{0}^{\pi}\frac{\sin(x)}{1+x}dx$
Work Step by Step
$$f(x_i)=\frac{\sin(x_{i})}{1+x_i} \Rightarrow f(x)=\frac{\sin(x)}{1+x} , a=0,b= \pi$$
so the given limit is equal to:
$$\int_{0}^{\pi}\frac{\sin(x)}{1+x}dx$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 4 - Integrals - 4.2 The Definite Integral - 4.2 Exercises - Page 317: 17
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