Answer
$y=x-1$
Work Step by Step
$$y=\frac{x^{2}+1}{x+1}$$
$$y=x+\frac{1-x}{x+1}$$
$$y=x-1+\frac{2}{x+1}$$
When $x$ goes to $\pm \infty$, the quantity $\frac{2}{x+1} \to 0$ so the slant asymptote is:
$$y=x-1$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 3 - Applications of Differentiation - 3.5 Summary of Curve Sketching - 3.5 Exercises - Page 250: 45
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