Answer
$$ \infty$$
Work Step by Step
Given
$$\lim _{x \rightarrow \infty}\left(x-\sqrt{x}\right)$$
Then
\begin{aligned}
\lim _{x \rightarrow \infty}\left(x-\sqrt{x}\right)&=\lim _{x \rightarrow \infty}\sqrt{x}\left(\sqrt{x}-1\right) \\
&=\lim _{x \rightarrow \infty}\sqrt{x}\lim _{x \rightarrow \infty}\left(\sqrt{x}-1\right)\\
&= \infty
\end{aligned}