Answer
$$-\infty$$
Work Step by Step
Given
$$\lim _{x \rightarrow -\infty}\left(x^2+2x^7\right)$$
Then
\begin{aligned}
\lim _{x \rightarrow -\infty}\left(x^2+2x^7\right)&=\lim _{x \rightarrow -\infty}x^7\left(\frac{x^2}{x^7}+2 \right)\\
&=\lim _{x \rightarrow -\infty}x^7\left(\frac{1}{x^5}+2 \right)\\
&=\lim _{x \rightarrow -\infty}x^7\lim _{x \rightarrow -\infty}\left(\frac{1}{x^5}+2 \right)\\
&=(-\infty)(2)\\
&=-\infty
\end{aligned}