Answer
$$\infty$$
Work Step by Step
Given
$$\lim _{x \rightarrow \infty}\sqrt{ x^2+1}$$
Then
\begin{aligned}
\lim _{x \rightarrow \infty}\sqrt{ x^2+1}&=\sqrt{\lim _{x \rightarrow \infty} (x^2+1)}\\
&=\sqrt{ \infty}\\
&=\infty
\end{aligned}
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 3 - Applications of Differentiation - 3.4 Limits at Infinity; Horizontal Asymptotes - 3.4 Exercises - Page 242: 26
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