Answer
$$f'(x) = bx^ax^{b-1}g'(x^b)+ax^{a-1}g(x^b)$$
Work Step by Step
Given $$f (x)= x^ag(x^b) $$
Then
\begin{align*}
f'(x)&= x^ag'(x^b)(bx^{b-1}) + ax^{a-1}g(x^b) \\
&= bx^ax^{b-1}g'(x^b)+ax^{a-1}g(x^b)
\end{align*}
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 2 - Derivatives - Review - Exercises - Page 198: 64
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
