Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 198: 63

Answer

$f'(x)=2g(x)g'(x)$

Work Step by Step

Given: $f(x)=[g(x)]^2$ By using power rule; $f'(x)=2[g(x)].g'(x)$ Hence, $f'(x)=2g(x)g'(x)$
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