Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 198: 62

Answer

$f'(x) = 2x g'(x^{2})$

Work Step by Step

$f(x) = g(x^{2})$ Use chain rule here $f'(x) = \frac{d}{dx} g(x^{2})$ $f'(x) = g'(x^{2}) \frac{d}{dx} (x^{2})$ $f'(x) = 2x g'(x^{2})$
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