Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 198: 61

Answer

$f'(x) = x^{2} g'(x) + 2x g(x)$

Work Step by Step

$f(x) = x^{2} g(x)$ Use chain rule here $f'(x) = x^{2} \frac{d}{dx}g (x) + g(x) \frac{d}{dx} x^{2} $ $f'(x) = x^{2} g'(x) + 2x g(x)$
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