Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.9 Linear Approximations and Differentials - 2.9 Exercises - Page 192: 3

Answer

$$y - 2 = 1/4(x-4)$$

Work Step by Step

To find the linearization we first need to calculate the slope by taking the derivative. $$f'(x) = 1/2* (x^{-1/2})$$ $$f'(4) = 1/2* (4^{-1/2})=1/2*2^{-1}= 1/4$$ Then we need to find the point where the line passes through, $$f(4) = 2$$ Using the point-slope form, $$y - 2 = 1/4(x-4)$$
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